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<![endif]--><div id="wrapper"><header id="sidebar" class="side-shadow"><hgroup id="site-header"><a id="site-title" href=".."><h2><i class="icon-pencil"></i> Блог 529</h2></a><p id="site-desc"> Project Euler и остальное </p></hgroup><nav><ul id="nav-links"><li><a href="../">Главная</a></li><li><a href="../pages/projects.html">Мои проекты</a></li><li><a href="../pages/about.html">Об авторе</a></li><li><a href="../feeds/feed.atom.xml">Atom feed</a></li></ul></nav><footer id="site-info"><p> Powered by Pelican. </p></footer></header><div id="post-container"><ol id="post-list"><li><article class="post-entry"><header class="entry-header"><time class="post-time" datetime="2016-10-21T17:40:00+03:00" pubdate> Пт 21 Октябрь 2016 </time><a href="../posts/moio-reshenie-zadachi-146/" rel="bookmark"><h1>Моё решение задачи&nbsp;146</h1></a></header><section class="post-content"><p>Краткое условие: необходимо найти сумму всех натуральных <span class="math">\(n\)</span>, что <span class="math">\(n^2+1\)</span>, <span class="math">\(n^2+3\)</span>, <span class="math">\(n^2+7\)</span>, <span class="math">\(n^2+9\)</span>, <span class="math">\(n^2+13\)</span>, и <span class="math">\(n^2+27\)</span> будут последовательными простыми&nbsp;числами.</p><script type="text/javascript">if (!document.getElementById('mathjaxscript_pelican_#%@#$@#')) {
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<![endif]--><div id="wrapper"><header id="sidebar" class="side-shadow"><hgroup id="site-header"><a id="site-title" href=".."><h2><i class="icon-pencil"></i> Блог 529</h2></a><p id="site-desc"> Project Euler и остальное </p></hgroup><nav><ul id="nav-links"><li><a href="../">Главная</a></li><li><a href="../pages/projects.html">Мои проекты</a></li><li><a href="../pages/about.html">Об авторе</a></li><li><a href="../feeds/feed.atom.xml">Atom feed</a></li></ul></nav><footer id="site-info"><p> Powered by Pelican. </p></footer></header><div id="post-container"><ol id="post-list"><li><article class="post-entry"><header class="entry-header"><time class="post-time" datetime="2016-10-30T17:40:00+03:00" pubdate> Вс 30 Октябрь 2016 </time><a href="../posts/moio-reshenie-zadachi-134/" rel="bookmark"><h1>Моё решение задачи&nbsp;134</h1></a></header><section class="post-content"><p>Краткое условие: назовём <em>порождающим</em> для двух последовательных простых <span class="math">\(p_1 &lt; p_2\)</span> наименьшее натуральное число, что оно закачивается на <span class="math">\(p_1\)</span> и при этом делится на <span class="math">\(p_2\)</span>. Необходимо найти сумму порождающих для всех <span class="math">\(p_1 \in \left[ 5; 10^6&nbsp;\right]\)</span></p><script type="text/javascript">if (!document.getElementById('mathjaxscript_pelican_#%@#$@#')) {
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<![endif]--><div id="wrapper"><header id="sidebar" class="side-shadow"><hgroup id="site-header"><a id="site-title" href=".."><h2><i class="icon-pencil"></i> Блог 529</h2></a><p id="site-desc"> Project Euler и остальное </p></hgroup><nav><ul id="nav-links"><li><a href="../">Главная</a></li><li><a href="../pages/projects.html">Мои проекты</a></li><li><a href="../pages/about.html">Об авторе</a></li><li><a href="../feeds/feed.atom.xml">Atom feed</a></li></ul></nav><footer id="site-info"><p> Powered by Pelican. </p></footer></header><div id="post-container"><ol id="post-list"><li><article class="post-entry"><header class="entry-header"><time class="post-time" datetime="2015-08-02T17:40:00+03:00" pubdate> Вс 02 Август 2015 </time><a href="../posts/crossgen-v10/" rel="bookmark"><h1>CrossGen&nbsp;v1.0</h1></a></header><section class="post-content"><p>Читая хабр, случайно натолкнулся на идею сделать программу, которая по заданной кроссвордной сетке находит способ её заполнить. В этом посте вкратце напишу про моё решение и первую версию&nbsp;приложения.</p></section></article></li><hr></ol><div class="paginator"> Page 1 / 1 </div></div></div><script type="text/javascript">
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